Originally Posted by
Brissieboy
Having a little trouble with some of the figures mentioned in this thread.
If the tyre diameter is 818mm and the width is at the front of the tyre is 1406mm and at the rear is 1409mm (that's how I interpret the OP's figures):
The 'toe-in' on each tyre (assuming equal on each) will be (1409-1406)/2 or 1.5mm.
Using basic trigonometry, the sine of the angle of the 'toe-in' is 1.5/818 (opposite over hypotenuse) = 0.0018337408312958.
Using inverse sine this equates to an angle of about 0.105degrees.
Does that make sense or have I got it all wrong?